Rocket Science

The force of gravity of the sun on an object is:

F = GM1M2 / r^2 = ma

At the radius of earth, this force is:
1.9891 × 10^30 kg x 6.67384 × 10^-11 m3 kg-1 s-2 / (149598261000 ^2).

a = .0059317 m/s^2 due to the Sun's gravitational pull.

v2^2 = v1^2 + 2ad

And V1 at about 10000 m/s (which might be the maximum velocity when the rocket escapes earth's axis.


0 = 10000^2 + 2*.0059317*d

Solve for d = 842,928,671km.

Now, of course the force of acceleration decreases the further you get out.

Saturn's orbit is 1,433,449,370 km and the force of acceleration there from the sun is only .00006460527m/2^2

So, we need to put a into an equation related to distance and solve.

Something I'll think about on the ride back to the falls today.